Please guide me in plotting the point with the given t-value,6 using
v=1/2t+6
Does v = 1/(2t+6) or or 1/(2t) + 6 or t/2 +6 ?
Whichever it is, plug in 6 for t and compute the resulting v.
This is what I am not grasping computing the formulas...
this formula is
v=1/2"fraction"t+6 with the given t-value, 6?
To plug in 6 for t, replace t in the equation with 6.
For example, given the equation y = x^2+x+5, to find y at x = 1, replace x in the equation with 1.
y = x^2 + x + 5 at x=1
y = 1^2 + 1 + 5
See how x is replaced by 1 in the equation?
So for v = (1/2)t + 6, how do you think you can find v at a t value of 6?
v=1/2(6)+6
1/2*6/1 = 6/2 with 2going into 6 - four times plus 6 equals 10? I have a feeling this is the not the correct way to solve for the equation given I replace the t with 6? Correct?
v=(1/2)(6)+6
That is correct. However, you seem to have calculated incorrectly. (1/2)*6 is 3, not 4.
v = 3+6
v = 9
I knew it!...this is my problem how did you calculate (1/2)*6 is 3...this is frustrating me..in getting the correct answers...I do not get it and I am a full blown adult - sorry :(
(1/2)*6 is the same as 6/2
6 = 2*3, so 6/2 = (2*3)/2. 2 cancels out, leaving you with 3.
ty
To plot the point with the given t-value of 6 using the equation v = 1/2t + 6, we need to substitute 6 into the equation to find the corresponding v-value.
Step 1: Substitute t = 6 into the equation v = 1/2t + 6.
v = 1/2(6) + 6
v = 3 + 6
v = 9
Step 2: We now have the coordinates for the point, which are (t, v) = (6, 9).
Step 3: Plot the point (6, 9) on a graph. The t-value of 6 corresponds to the x-axis, and the v-value of 9 corresponds to the y-axis.
Step 4: Mark the point (6, 9) on the graph using a dot or an 'x' to represent the coordinates.
That's it! You have successfully plotted the point with the given t-value of 6 using the equation v = 1/2t + 6.