Given that p=(2q^2-5)^2. when q=3, it is increased by 0.7%. find the appropriate percentage in p.
solution
dp = 2(2q^2-5) (2dq)
dp = (4x(18-5)(0.7%)
dp = 4(13)(0.7%)
am lost from here
is dp=52x0.7/100= 0.364%
p=(2q^2-5)^2
dp=2(2q^2-5)(4q)dq
check that.