# Differential Calculus

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Given that p=(2q^2-5)^2. when q=3, it is increased by 0.7%. find the appropriate percentage in p.

solution
dp = 2(2q^2-5) (2dq)
dp = (4x(18-5)(0.7%)
dp = 4(13)(0.7%)

am lost from here

is dp=52x0.7/100= 0.364%

• Differential Calculus -

p=(2q^2-5)^2

dp=2(2q^2-5)(4q)dq

check that.

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