(1) lim x^3 - 125/x--;5 x^2 - 25

Question

(1) lim x^3 - 125/x--;5 x^2 - 25

1. Lim as x approaches what? arrow sign

Answer 1

Perhaps you mean

Lim (x^3-125)/(x^2-25)
x->5

Since the expression approaches 0/0 at x=5, take the ratio of derivatives, which is 3x^2/2x = 1.5 x. The limit is therefore 7.5 when x->5

This method is called using L'Hopital's rule.

Answer 2

In the given expression, "lim x^3 - 125/x; x^2 - 25", there seems to be an inconsistency. It is not clear what the limit is being taken of. Could you please clarify the expression or provide more information so I can assist you better?