# Math

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On a TV game show, the contestant is asked to select a door and then is rewarded with the prize behind the door selected. If the doors can be selected with equal probability, what is the expected value of the selection if the three doors have behind them a \$40,000 foreign car, a \$3 silly straw, and a \$50 mathematics textbook?
Answer: 1/3 but I don't think that this correct.
Thanks.

• Math -

OF course it is not correct. Expected Value is in dollars.

EV=1/3(40,000) + 1/3 (3) + 1/3 (50)

http://en.wikipedia.org/wiki/Expected_value

• Math -

So then, my answer should be this:
13,333.33333+1+16.66666667= 13,351 is this correct?
Thanks.

• Math -

"Expected Value is in dollars."

• Math -

Thanks.

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