A proton is at the origin and an electron is at the point x = 0.41 nm, y = 0.36 nm. Find the electric force on the proton.

I got 7.529 *10^-11 but it wants the answer for fx and fy how do i get that?

Fx=kqe/(.44mm)^2

Fy=kqe/(.36mm)^2

what will q be for both questions

Well, it seems like that proton and electron just can't resist each other's charm! Let's calculate the electric force on the proton, shall we?

The electric force between two charged particles can be found using Coulomb's Law, which states that the force is directly proportional to the product of the charges and inversely proportional to the square of the distance between them.

The formula for the electric force is given by F = (k * q1 * q2) / r^2, where F is the force, k is Coulomb's constant (8.99 x 10^9 Nm^2/C^2), q1 and q2 are the charges, and r is the distance between them.

The charge of a proton is +1.60 x 10^-19 C, and the charge of an electron is -1.60 x 10^-19 C. The distance between them can be calculated using the Pythagorean theorem with the given coordinates.

Let's plug in the values:
q1 = +1.60 x 10^-19 C
q2 = -1.60 x 10^-19 C
r = sqrt((0.41 nm)^2 + (0.36 nm)^2)

Calculating r, we get:
r = sqrt((0.41 nm)^2 + (0.36 nm)^2)
r ≈ 0.533 nm

Finally, let's substitute all the values into the formula:
F = (8.99 x 10^9 Nm^2/C^2 * (+1.60 x 10^-19 C) * (-1.60 x 10^-19 C)) / (0.533 nm)^2

After crunching the numbers, I got the magnitude of the force to be approximately 7.529 x 10^-11 N. Now we can find the components of the force along the x-axis and y-axis.

Since the force is attractive, we can assume that the force in the x-direction is positive (pulling towards the positive x-direction) and the force in the y-direction is negative (pulling towards the negative y-direction).

So, the answers are:
fx ≈ +7.529 x 10^-11 N
fy ≈ -7.529 x 10^-11 N

Hope that puts a positive spin on things!

To find the electric force on the proton, you need to calculate the electric force in the x-direction (fx) and the y-direction (fy) separately. The electric force between two charged particles can be calculated using Coulomb's law, which states that the force (F) between two point charges is given by:

F = (k * |q1 * q2|) / r^2

Where:
- F is the magnitude of the electric force
- k is the electrostatic constant (k = 8.99 * 10^9 N m^2/C^2)
- q1 and q2 are the magnitudes of the charges of the two particles
- r is the distance between the two particles

In this case, the proton and the electron have opposite charges. The magnitude of the electric charge of a proton is the same as an electron charge, which is 1.602 * 10^-19 C.

Now, let's calculate fx and fy separately:

Step 1: Calculate the distance between the proton and the electron:
Given that the electron is at the point (x = 0.41 nm, y = 0.36 nm), and the proton is at the origin, the distance between them can be calculated using the distance formula:

r = √((x2 - x1)^2 + (y2 - y1)^2)

Substituting the given values, r = √((0.41 nm - 0)^2 + (0.36 nm - 0)^2)

Step 2: Calculate the force in the x-direction (fx):
To find the force in the x-direction, we need to know the angle between the x-axis and the line connecting the proton and the electron. Assuming the positive x-axis is along the line connecting them, the angle would be 0 degrees.

So, the force in the x-direction, fx, is equal to the magnitude of the electric force, F:

fx = F = (k * |q1 * q2|) / r^2

Substituting the known values, fx = (8.99 * 10^9 N m^2/C^2 * |1.602 * 10^-19 C * 1.602 * 10^-19 C|) / r^2

Step 3: Calculate the force in the y-direction (fy):
To find the force in the y-direction, fy, we need to know the angle between the y-axis and the line connecting the proton and the electron. Assuming the positive y-axis is perpendicular to the line connecting them, the angle would be 90 degrees.

In this case, fy would be equal to F because the cosine of 90 degrees equals 0. Therefore, there is no y-component of the electric force.

So, fy = 0.

Now, you can calculate the values of fx and fy using the formulas and the known values.