MATH
posted by NANCY .
I HAVE A GARDEN THE WIDTH OF MY GARDEN IS 8FT LONGER THAN THE LENGHT OF IT ARUOUND THE GARDEN I HAVE A 4 FEET WIDE SIDEWALK. THE AREA OF THE SIDEWALK IS ABOUT 320 FEET SQUARE, WHAT ARE THE DIMENSIONS OF MY GARDEN

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To solve the problem, you would let one side of the garden be x feet. Then the longer side will be (x+8) feet. The area of the garden is therefore A1 = x(x+8) sq. ft.
COntinue this way to calculate the rectangle that includes the footpath and the garden, all expressed in terms of x and numbers. Calculate similarly the area, A2, in sq. ft.
The question suggest that A2  A1 = 320 sq. ft. So form the equation and solve for x.
It will be a single linear equation in one unknown x, which you will need to find.
Give it a try and post your results.
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