Algebra Help

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Let x = log_2 1/8

Write the exponential form of the equation and solve the equation for x.

Does this work? Thanks!

Exponential form is 2^-3=1/8

To Check:
2^-3=1/2^3=1/8

  • Algebra Help -

    Please continue with post below, you are almost there!
    http://www.jiskha.com/display.cgi?id=1249473232

  • Algebra Help -

    x = log_ 2 2^-3

    ? I am lost now. I really thought I had it from what I just posted.

    Exponential form is 2^-3 = 1/8 This isn't correct?

    To Check:
    2^-3=1/2^3=1/8

  • Algebra Help -

    Exponential form is 2^-3 = 1/8 This isn't correct?
    This part is correct, that's the "so far so good" part. Sorry if there was a misunderstanding.

    You also need to do the second part: " and solve the equation for x."

    You are very close to finishing, keep it up.

  • Algebra Help -

    Solve for x i got, the exponential is the problem for me...Here is what i got for x.

    To Solve:

    1/8=8^-1
    8=2^3
    1/8=2^3^-1=8^-1
    =2^-3
    Log_2 1/8 = log_2 2^-3

    =-3log_2 2

    x =-3

    To Check:

    2^x=1/8= 2^-3

    x=-3

  • Algebra Help -

    Correct!

  • Algebra Help -

    Now what about the Exponential form
    ?

    2^-3 = 1/8 This isn't correct? If not then how do i show Let x = log_2 1/8 in exponential form?

  • Algebra Help -

    "Algebra Help - MathMate, Wednesday, August 5, 2009 at 6:41pm

    Exponential form is 2^-3 = 1/8 This isn't correct?
    This part is correct, that's the "so far so good" part. Sorry if there was a misunderstanding. "

    The exponential form has to be correct for you to proceed with the second part, otherwise the second part will not be correct.

  • Algebra Help -

    Thank you this really helps! So I got

    Exponential form is 2^-3 = 1/8

    and To solve x = -3 So this is all of it?

  • Algebra Help -

    That's all there is to it.

    If you have time, read up and understand of the identities listed earlier. You'll be glad you did when exam comes around.

  • Algebra Help -

    Thanks! You have been a BIG help! I will do that!

  • Algebra Help -

    It's been a pleasure!

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