# Algebra Help

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Let x = log_2 1/8

Write the exponential form of the equation and solve the equation for x.

Does this work? Thanks!

Exponential form is 2^-3=1/8

To Check:
2^-3=1/2^3=1/8

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Please continue with post below, you are almost there!
http://www.jiskha.com/display.cgi?id=1249473232

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x = log_ 2 2^-3

? I am lost now. I really thought I had it from what I just posted.

Exponential form is 2^-3 = 1/8 This isn't correct?

To Check:
2^-3=1/2^3=1/8

• Algebra Help -

Exponential form is 2^-3 = 1/8 This isn't correct?
This part is correct, that's the "so far so good" part. Sorry if there was a misunderstanding.

You also need to do the second part: " and solve the equation for x."

You are very close to finishing, keep it up.

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Solve for x i got, the exponential is the problem for me...Here is what i got for x.

To Solve:

1/8=8^-1
8=2^3
1/8=2^3^-1=8^-1
=2^-3
Log_2 1/8 = log_2 2^-3

=-3log_2 2

x =-3

To Check:

2^x=1/8= 2^-3

x=-3

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Correct!

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Now what about the Exponential form
?

2^-3 = 1/8 This isn't correct? If not then how do i show Let x = log_2 1/8 in exponential form?

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"Algebra Help - MathMate, Wednesday, August 5, 2009 at 6:41pm

Exponential form is 2^-3 = 1/8 This isn't correct?
This part is correct, that's the "so far so good" part. Sorry if there was a misunderstanding. "

The exponential form has to be correct for you to proceed with the second part, otherwise the second part will not be correct.

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Thank you this really helps! So I got

Exponential form is 2^-3 = 1/8

and To solve x = -3 So this is all of it?

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That's all there is to it.

If you have time, read up and understand of the identities listed earlier. You'll be glad you did when exam comes around.

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Thanks! You have been a BIG help! I will do that!

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It's been a pleasure!