Chemistry

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A solution is made by mixing 35.0 mL of toluene C6H5CH3d=0867gmL with 125.0 mL of benzene C6H6d=0874gmL. Assuming that the volumes add upon mixing, the molarity (M) and molality (m) of the toluene are

  • Chemistry -

    Molarity=molestoluene/volumesolutioninliters

    molality= molestoulene/(kg benezene)

    Do you have any questions on how to do these?

  • Chemistry -

    how do you get the volume of the solution

  • Chemistry -

    and how do you get moles of toluene? please

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