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What volume of 16 M nitric acid must be diluted with distilled water to prepare 500.0 mL of 0.50 M HNO3?

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    500 ml of the diluted 0.50 M nitric acid will contain 0.25 moles of HNO3.
    1/64 liter of 16M nitric acid contains 16/64 = 0.25 moles of HNO3. So 1/64 liter (62.5 mL) is the answer.

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