solve: x^2+10x+4=0

I would use the quadratic equation to get the factors.

I know about the quadratic equation, I can never do it correctly or seem to get the right answer, I do excerises with my school work and follow the steps but can't seem to do it with out looking at how someone else got the answer first. I am horriable at math and this is my last math class. Can you help me?

It is important that you are capable to do these exercises unless you do not expect to pass your exam.

If you send in your calculations, with or without mistakes, we will be glad to give you our comments so you will be able to make the appropriate corrections.
By the way, the quadratic formula for an equation
y = Ax² + Bx + C
is
x = (-B ± √(B²-4AC))/(2A)
Give it a try.

ok is the answer x=-5 plus-minus sqrt 21?

Well done!

The answer is correct!
If you memorize the quadratic formula, you would certainly make a champion at the exams.

To solve the quadratic equation x^2 + 10x + 4 = 0, we can use the quadratic formula, which is:

x = (-b ± √(b^2 - 4ac)) / (2a)

In this equation, a, b, and c represent the coefficients of the quadratic equation. Comparing the given equation to the standard quadratic form, we can identify:

a = 1
b = 10
c = 4

Now, substitute these values into the quadratic formula and simplify:

x = (-(10) ± √((10)^2 - 4(1)(4))) / (2(1))
x = (-10 ± √(100 - 16)) / 2
x = (-10 ± √84) / 2
x = (-10 ± √(4 * 21)) / 2
x = (-10 ± 2√21) / 2
x = -5 ± √21

Thus, the solutions for the given quadratic equation are x = -5 + √21 and x = -5 - √21.