Post a New Question


posted by .

in order for piece of rectangular luggage to fit in the overhead compartment of a certain airplane, the sum of the height of the luggage and the perimeter of the base of the luggage must be less than or equal to 110 inches. If a piece of luggage has a height of 20 inches and a width of 15 inches, what is the maximum possible length of the luggage?

is the correct answer 30?

  • math -


    They are saying :

    height + base 1 + base 2 + base 3 + base 4 has to be equal to or less than 110 inches.

    You're right because there are 4 lines in the perimeter of the base. If you draw a square or rectangle, it has four lines.

    2 of those lines are 15 inches. 15x2 = 30.

    The height is 20.

    30+20 = 50

    So you have 60 inches to play with. They did not tell you the length of the luggage, but on that square, the length takes up 2 sides of the square. So 60 inches left over divided by the 2 sides of the rectangle left over = 30 inches per side.

    Nice work!

Respond to this Question

First Name
School Subject
Your Answer

Similar Questions

More Related Questions

Post a New Question