Algebra
posted by Crystal .
Let f(x) =(x+3)/(2x5)
Find the inverse function of f
What is the domain of f? What is the domain of the inverse function?

Let f(x) = y
Then solve for x in terms of y.
(2x5)y = x + 3
2xy 3 = 5y + x
x(2y 1)= 5y + 3
x = (5y+3)/(2y1)
That is the inverse function. It can be written
f^1(x)= (2x+3)/(2x1)
The domain of f(x) is all numbers except 5/2.
The domain of f^1(x) is all numbers except 1/2 
Thank you for showing me! Now I can do the rest on my own hopefully without a problem! Thanks again!
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