find the slope, if it exists, of the line containing the pair of points
(9,5) and (10,-3)
teh slope m= 1.2
m=(-3+9)/ (10-5)
m=6/5
m=1.2
Sorry, your answer is not correct. It is a big negative number.
The slope of a line passing between two points P1(x1,y1) and P2(x2,y2) is
m=(y2-y1)/(x2-x1) provided (x2-x1)≠0
I leave it to you to recalculate the slope required. Post your answer for verification if required.
M= (y2-y1)/(x2-x1)
so (-3-5)/(10-9)=-7
For -3-5 I get -8.
To find the slope of a line passing through two points, you can use the formula:
m = (y2 - y1) / (x2 - x1),
where (x1, y1) and (x2, y2) are the coordinates of the two points.
In this case, the given points are (9,5) and (10,-3). Plugging these values into the formula, we have:
m = (-3 - 5) / (10 - 9)
= -8 / 1
= -8.
Therefore, the slope of the line passing through these two points is -8.