write the equatopm pf a line that passes through(3,-1) and is parrallel to the line y=-2x+1
doing it the easiest way ...
we know that the new equation differs only in the constant at the end, since the two lines are parallel.
so let the new equation be y = -2x + b
sub in the point...
-1 = -2(3) + b
5 = b
so y = -2x + 5