Please help! Thanks.
An ammonia solution is made by diluting 0.105L of the concentrated commercial reagent until the final volume reaches 1.00L. What is the final molar concentration?
What is the concentration of commercial NH3. Are you supposed to calculate that, too. If so, you don't have enough information. Commercial ammonia is about 28% NH3 and it is about 15 M.
15 M x 0.105/1000 = ??
To find the final molar concentration of the ammonia solution, we need to know the initial molar concentration of the concentrated ammonia solution.
Let's assume that the concentrated ammonia solution has an initial molar concentration of x mol/L.
We can use the principle of the conservation of moles to find the final molar concentration.
The number of moles of the concentrated ammonia solution is given by:
Number of moles = initial molar concentration x initial volume
Number of moles = x * 0.105L
Since we are diluting the solution, the number of moles remains the same before and after dilution. Therefore, the number of moles of the dilute ammonia solution remains the same.
The final volume of the diluted ammonia solution is 1.00L. So, the final molar concentration can be calculated as:
Final molar concentration = Number of moles / final volume
Final molar concentration = (x * 0.105L) / 1.00L
Simplifying the expression, we find that the final molar concentration is 0.105x mol/L.
Therefore, the final molar concentration of the ammonia solution depends on the initial molar concentration of the concentrated ammonia solution.