Algebra

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Please Solve:

(x+3)(x-5) < 0

I got so far on this and am lost..

(x+3 <0 and x-5>0) OR (x+3>0 and x-5<0)
(x<-3 and x > 5) OR (x> and x<5)
(x<-3 and x>5) OR (-3<x<5)



Do we use FOIL for this cause if we do i did this:

x^2-5x+3x-15
x^2-5x+3x-15
x^2-2x -15 >0
x^2 -4x-15>0

x<5, x<-3

x=-3 & x=5


Is any of this correct?

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