a traffic sign is in the shape of an isosceles triangle. each of the equal sides is 5in.longer than tice the base.if the perimeter is 80in., find the length of the base?
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First. Perimeter= b+L+L
Perimeter=b+5+b + 5 + b
you are given perimeter , solve for b, the base
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oh ok ty drBob222. in order to solve this problem do i use the formula isosceles? and thank you so much for helping me!
To find the length of the base of the traffic sign, we can set up an equation using the given information.
Let's assume that the length of the base of the isosceles triangle is "x" inches. As stated in the question, each of the equal sides is 5 inches longer than twice the base. So, the length of each equal side can be represented as (2x + 5) inches.
The perimeter of the triangle is given as 80 inches, which is the sum of all three sides. Therefore, we can write the equation as:
x + (2x + 5) + (2x + 5) = 80
Now, solve the equation to find the value of "x," which will give you the length of the base:
x + 2x + 5 + 2x + 5 = 80
5x + 10 = 80
5x = 80 - 10
5x = 70
x = 70 / 5
x = 14
Hence, the length of the base of the traffic sign is 14 inches.
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