a garden center sells shrubs in two different sizes.A small shrub costs 18.00 and a large one costs 32.00. in one day,65 shrubs were sold for a total of 1520.00. how many large shrubs were sold?
Let S = number of small shrubs
let L = number of large shrubs
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The two equations are as follows:
S + L = 65
18S + 32L = 1520
Solve the two equations for L and S. Post your work if you get stuck.
i don't know how to solve this
Multiply equation 1 by -18 and add the result to equation 2. That will eliminate S. Solve for L as you would any algebra equation.
To solve this problem, we can set up a system of equations. Let's denote the number of small shrubs sold as 's' and the number of large shrubs sold as 'l'.
From the problem, we know the following information:
1) The cost of a small shrub is $18.00.
2) The cost of a large shrub is $32.00.
3) In one day, a total of 65 shrubs were sold.
4) The total revenue from the sales of these shrubs was $1520.00.
Based on this information, we can form two equations:
Equation 1: s + l = 65 (since the total number of shrubs sold is 65)
Equation 2: 18s + 32l = 1520 (since the total revenue from the sales of shrubs is $1520.00)
Now, we can solve this system of equations to find the values of 's' and 'l'.
Method 1: Substitution Method
From Equation 1, we know s = 65 - l. We can substitute this value of s into Equation 2:
18(65 - l) + 32l = 1520
Simplifying the equation:
1170 - 18l + 32l = 1520
14l = 350
l = 25
Therefore, 25 large shrubs were sold.
Method 2: Elimination Method
We can multiply Equation 1 by 18 and Equation 2 by 65 to eliminate 's':
18s + 18l = 1170
18s + 32l = 1520
Subtracting the two equations:
(18s + 32l) - (18s + 18l) = 1520 - 1170
14l = 350
l = 25
Therefore, 25 large shrubs were sold.
In conclusion, 25 large shrubs were sold on that day.