Algebra
posted by Crystal .
.04x + 720  .06x > = 650
.02x <= 70
x < = 70/.02
x < = 3500
Or do the sign go the other way like this?
.04x + 720  .06x > = 650
.02x > = 70
x > = 70/.02
x > = 3500
Which would be the solution to solve this inequality?
.04 x + .06(12000x) >= 650

see my final reply to
http://www.jiskha.com/display.cgi?id=1247546252 
Why is is greater than or = to? I got the answer as being < or = 3500? Can you please explain? Thanks!

Yes, I had agreed that you were right,
and changed it to ≤
here is the corrected version
.04x + 720  .06x ≥ 650
.02x ≥ 70
x ≥ 70/.02
x ≤ 3500 
So basically the > = stay the same for the first 2 lines and change to < = for the last? How does that work?

Ok, I will illustrate with an example
e.g.
8 > 5 > True
if we add any number or subtract any number the statement is still true
8+6 > 5+6 > True
let's multiply by a positive number
8(4) > 5(4) > still True !
how about dividing by a positive
8/2 > 5/2 ??? Yes, still True
how about multiplying by a negative
8(3) > 5(3) or
24 > 15 BUT THAT IS FALSE !!!
how do we make it true? We reverse the sign
24 < 15 , now it's Truee
same thing for division by a negative.
So, in summary,
you can add/subtract any value just like for equations and the inequality sign stays the same.
Same is true for multiplying/dividing by a positive number.
BUT, when you multiply or divide by a negative number in an inequality, you have to reverse the inequality sign at that step. Usually this will be your last step. 
Thank you! This is a great review of this topic! Thanks again!
Respond to this Question
Similar Questions

bobpursly, check please,math
do you mean like this: 720/(V30) + 720/(V+30) = 10 Get a common denominator of (v30)(v+30) then multiplying both sides by that, then (v30)(v+30)X 720(V+30) + (v30)(v+30) X 720(V30)=(v30)(v+30)X 10(v30)(v+30) then multily out, … 
Math
how do you do a problem like this? 720m/day=? 
math
I need help in solving this subtraction (0.06x^30.07x^2+0.04x)(0.02x^3+0.07x^29) 
Algebra
Please solve the inequality .04 x + .06(12000x) >= 650 .04x + 720  .06x ¡Ý 650 .02x ¡Ý 70 x ¡Ý 70/.02 x ¡Ý 3500 I think this is wrong and what is below is correct? 
ALGEBRA
for subtracting this problem: (0.04x^30.03x^2+0.02x)(0.03x^3+0.08x^26) I know to change the signs of the second grouping. When I done that, I cam up with: 0.04x^30.03x^2+0.02x0.03x^30.08x^2+6 THEN .01x^3  .11x^2 + 0.02x + 6.....is … 
Algebra
R(x)= 360x  0.04x^2 
Math
Is there another way to write this equation? 
Chemistry
A 360mL sample of hydrogen is collected when the pressure is 800 mm Hg. What is the volume that the gas will occupy when the pressure is 720 mm Hg? 
algebra
solve the system by substitution x+y=9000 .06x+.15y=1215 .06x+.15(x9000)=1215 .06x+.15x1350=1215 .21x1350=1215 x1350+1214.79 x+2564.79 don't look right? 
7th Grade Math
Sarah has $200 to spend. She buys a chair for x dollars and pays 6% sales tax. She has y dollars left. What equation models this situation?