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Set theory

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consider the relation R=[(1,2),(2,5),(3.10),(4,17),(5,26)]. find the
i)range ii)domain iii)inverse

  • Set theory -

    Assuming the relation is
    f(x)=y=x2+1 where x ∈ ℕ (i.e. x is a member of natural numbers), then the domain is
    {x:[1,5] ∈ ℕ}
    Range is
    {y:[2,26] ∈ ℕ}
    Inverse:
    f-1(y) = sqrt((y-1)) : f-1(y)>0

  • Set theory -

    Correction for range, which is the set of all values produced by the function within the given domain. For the above relation
    f(x)=y=x2+1,
    the domain is
    {1,2,3,4,5}
    the range is
    {2,5,10,17,26}
    The inverse is as above.

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