Set theory

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consider the relation R=[(1,2),(2,5),(3.10),(4,17),(5,26)]. find the
i)range ii)domain iii)inverse

  • Set theory -

    Assuming the relation is
    f(x)=y=x2+1 where x ∈ ℕ (i.e. x is a member of natural numbers), then the domain is
    {x:[1,5] ∈ ℕ}
    Range is
    {y:[2,26] ∈ ℕ}
    f-1(y) = sqrt((y-1)) : f-1(y)>0

  • Set theory -

    Correction for range, which is the set of all values produced by the function within the given domain. For the above relation
    the domain is
    the range is
    The inverse is as above.

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