I have two questions this one

A 750-N force acts in a northweserly direction. A secon 750-N force must be exerted in what direction so that the resultant of the two forces points westward?

I have no idea how to go about solving this prolbem

second

Draw the free body diagram fora basketball player just before leaving the ground on a jump, and while in the air.

ok while the player is in the air the forces acting on him are gravity right? mg pointing downard, the nomral force exerted by the air particls pushing upward and the equal and opposite reaction of the normal force the F'n right point downwards. Is that correct? Isn't there still a normal force while in the air sense the air particles are elastic they exert a normal force onto the player???

1. If you want to resultant to point west, then you must cancel out the northern part of the first force. The two forces are of the same magnitude, so have the same force at a direction that will create an equal and opposing force in the northerly direction - southwest.

ok uh I still don't completly understand I thought I was trying to get it to point westward not south west

also what about the basketball player question

Marth told you the correct answer for the first problem.

If you push NW and SW at the same time with equal forces, you end up accelerating west. Draw the arrows.

In the second problem just before takeoff there is a force mg down (gravity). There is also a force up on the player from the floor which is greater than mg so the player accelerates upwards. Once the player is in the air, only mg down remains (ignoring air friction) and the player accelerates toward the floor until he comes back down and hits the floor.

1. The first force has north and west components. To get it to point only west, you must nullify the north components.

2. I cannot draw diagrams here, but I can describe the forces.

Just before the player leaves the ground, there is
a) the force of weight
b) the normal force from the ground
c) an upwards force exerted by the player to start the jump

With the player in the air, there is
a) the force of weight

Air does not create a normal force. While in the air the player only experiences the force of weight.

Please note that gravity (in this context) is not a force, it is an acceleration. The force of weight is affected by the player's mass and the gravitational acceleration of earth.

Let's break down each question and explain how to solve them:

First question:

We have a 750-N force acting in a northwest direction. We need to find the direction of the second 750-N force such that the resultant points westward.

To solve this problem, we can break the given force vectors into their components. Since the first force is acting in the northwest direction, we can split it into its north and west components. In this case, the north component would be 750 N * sin(45°) and the west component would be 750 N * cos(45°).

Now, to find the direction of the second force, we need to make sure the west component of the second force cancels out the west component of the first force (since we want the resultant to point westward). Therefore, the second force needs to have a west component of 750 N * cos(45°).

However, we also need to consider the north component of the second force. Since we want the resultant to have no northward motion, the north component of the second force needs to cancel out the north component of the first force. Therefore, the second force needs to have a north component of -750 N * sin(45°).

Putting it all together, the second force must be exerted in the direction that has a west component of 750 N * cos(45°) and a north component of -750 N * sin(45°).