Math

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PLease help with this problem. My friend and I differ on answer.

(3abc^2 )^4/(7a^2 b)^4 =

  • Math -

    81c^8/2401a^4.'
    There may be a factor for 81 and 2401 but it isn't obvious if there is one.

  • Math -

    thank you very much, my friend was right I was wrong

  • Math -

    2401 = 7*7*7*7
    81 = 3*3*3*3
    There are no common factors

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