# Math

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April buys eight books for \$44. Paper back books cost \$4 and hard back books cost \$8. How many of

• Math -

4 paper backs and 4 hard cover

• Math -

Hmm -- that's not right.

4 * 4 = 16
4 * 8 = 32

16 + 32 = 48.

Ooops!

• Math -

For this kind of problem, I usually start off with all paperbacks, thus 8*4=\$32.
Since I am short 44-32=\$12, and changing from a paperback to a hard-cover costs 8-4=\$4, So I must have bought 3 hard-covers and 8-3=5 paperbacks.
Check: 3*8+5*4=24+20=\$44.

• Math -

And then there's the LONG way of doing it.
H = number of hard covers.
P = number of paper covers.
===========================
H + P = 8
8H + 4P = 44.
================
Two equations in two unknowns. Solve for H and P.

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