a car of mass 900 kg moves at 10 m/s. what is the braking force required to stop the car in a time of 5 seconds?
Find the required acceleration.
a = (Vf-Vi)/t
where Vf = final velocity and Vi = initial velocity
You want final velocity to be 0.
a = (0-10)/5
a = -2 m/s/s
Now to find the force:
F = ma
F = 900*-2
F = -1800N
The force required is 1800N applied opposite from the direction of motion.
To find the required braking force to stop the car, we can use Newton's second law of motion, which states that force is equal to mass multiplied by acceleration (F = m * a). In this case, the acceleration is the rate of change of velocity, which can be calculated by dividing the change in velocity by the time taken to achieve that change.
Given:
Mass (m) = 900 kg
Initial velocity (u) = 10 m/s
Final velocity (v) = 0 m/s (since the car needs to come to a stop)
Time (t) = 5 s
First, we need to calculate the acceleration (a):
a = (v - u) / t
a = (0 - 10) / 5
a = -10 / 5
a = -2 m/s²
Since the car is decelerating, the acceleration is negative.
Now that we have the acceleration, we can calculate the required braking force (F):
F = m * a
F = 900 kg * -2 m/s²
F = -1800 N
Therefore, the required braking force to stop the car in 5 seconds is 1800 Newtons (N).