what is the product of the solutions to the equation x squared minus 15x minus 36 equal -72
x^2-15x-36=-72
therefore x^2-15x+36=0
when you solve this you get
(x-12)*(x-3)=0
You can find the 2 solutions from that and multiply them.
hope that helps
To solve the equation x^2 - 15x - 36 = -72, you need to find the values of x that satisfy the equation. The product of these solutions is equal to the constant term (-72) divided by the coefficient of the squared term (1).
Let's solve the equation step by step:
1. Start by moving all the terms to one side of the equation:
x^2 - 15x - 36 + 72 = 0
Rearrange the terms:
x^2 - 15x + 36 = 0
2. Next, we need to factorize the quadratic equation if possible:
The equation factors as (x - 12)(x - 3) = 0
3. Set each factor equal to zero and solve for x:
x - 12 = 0 or x - 3 = 0
x = 12 or x = 3
4. So the solutions to the equation are x = 12 and x = 3.
Finally, to find the product of the solutions, multiply the two values together:
Product of solutions = 12 * 3 = 36