An object is thrown upwards with a speed of 14.0 m/s. How long does it take to reach its maximum height
use the formula
v=u+at
where
v= final velocity (0)
u= initial velocity (+14 m/s)
a= acceleration du to gravity, -9.81 m/s/s
negative because it accelerates in the negative y-direction.
t= time in seconds
1.43
To find how long it takes for an object to reach its maximum height, we need to know the acceleration due to gravity and the initial velocity. The acceleration due to gravity near the Earth's surface is approximately 9.8 m/s².
The object is thrown upwards, so its initial velocity is positive 14.0 m/s. At the maximum height, the object will momentarily stop before it begins to descend. At this point, its final velocity will be zero.
Using the kinematic equation:
vf = vi + at
Where:
vf = final velocity
vi = initial velocity
a = acceleration
t = time
We can plug in the known values: vf = 0 m/s, vi = 14.0 m/s, and a = -9.8 m/s² (negative because it is acting in the opposite direction).
0 = 14.0 - 9.8t
Simplifying the equation, we have:
9.8t = 14.0
Now we can solve for t:
t = 14.0 / 9.8
Evaluating the expression gives us:
t ≈ 1.43 seconds
Therefore, it takes approximately 1.43 seconds for the object to reach its maximum height.