factorize completely

3mn-6n^2 3n(m-2n) is this correct?

correct

Yes, your factorization is correct. The expression 3mn - 6n^2 can be fully factorized as 3n(m - 2n).

Yes, your factorization is correct. You have correctly factored out the greatest common factor of the terms, which is 3n. After factoring out 3n, you are left with (m-2n). Therefore, the complete factorization of 3mn - 6n^2 is 3n(m-2n).