chemistry

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The heat capacity of object B is twice that of object A. Initially A is at 300 K and B is at 450 K. They are placed in thermal contact and the combination is isolated. The final temperature of both objects is:

  • chemistry -

    Let the heat capacity of A = c. The heat capacity of B is 2c. Let the final temperature be T.
    The heat lost by B when A and Be are placed together is: (2c)(450-T)
    The heat gained by A is (c)(T-300).
    Assuming the Law of conservation of Energy holds, and there are no heat losses (heat transferred elsewhere),
    (2c)(450-T) = (c)(T-300)
    Solve for T.

  • chemistry -

    The basic relationships above are:

    1. Heat transferred = (heat capacity)(temperature change), or
    deltaH = C•(T2-T1)
    ( T1, T2 = initial and final temperatures )

    2. Heat lost by B = Heat gained by A

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    400k

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