I have a problem answering this certain question, can you help me? The hydraulic system on a forklift contains 7/8 gallon of hydraulic fluid. A cracked seal resulted in a loss of 1/6 gallon of fluid in the morning and another 1/3 gallon in the afternoon. Find the amount of fluid remaining
1/6 + 1/3 = 1/6 + 2/6 = 3/6 = 1/2
7/8 - 1/2 = 7/8 - 4/8 = 3/8
The interest rate on an auto loan in May was 12 3/8%. By September the rate was up to 14 1/4%. How many percentage points did the interest rate increase over the period?
Of course, I'd be happy to help you with that question! To find the amount of fluid remaining in the hydraulic system, we need to subtract the lost fluid from the initial amount.
Let's break down the information given:
- The hydraulic system contains 7/8 gallon of hydraulic fluid.
- There was a loss of 1/6 gallon of fluid in the morning.
- There was another loss of 1/3 gallon of fluid in the afternoon.
To find the amount of fluid remaining, we'll subtract the sum of the lost fluids from the initial amount.
First, let's find the total lost fluid:
1/6 gallon (morning loss) + 1/3 gallon (afternoon loss)
To add fractions together, we need a common denominator. In this case, the least common denominator (LCD) is 6.
(1/6) gallon = (1/6) * (6/6) = 6/36 gallon
(1/3) gallon = (1/3) * (2/2) = 2/6 gallon
Now, let's add the fractions:
6/36 gallon + 2/6 gallon
To add fractions, both fractions need to have the same denominator. In this case, they already have a common denominator of 36.
So, we can just add the numerators:
6/36 + 2/36 = 8/36 gallon
Now that we have the total lost fluid, we can find the remaining fluid by subtracting the lost fluid from the initial amount:
7/8 gallon (initial amount) - 8/36 gallon (lost fluid)
Again, to subtract fractions, they should have the same denominator. In this case, we can convert 7/8 to have a denominator of 36.
(7/8) * (4/4) = 28/36 gallon
Now, let's subtract:
28/36 gallon - 8/36 gallon = 20/36 gallon
To simplify the fraction, we can reduce it by dividing the numerator and denominator by their greatest common divisor (GCD), which is 4:
(20/4) / (36/4) = 5/9 gallon
So, the amount of hydraulic fluid remaining in the system is 5/9 gallon.
I hope this explanation helps you understand how to solve the problem! Let me know if you have any other questions.