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physics please!

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A 0.21 kg block oscillates back and forth along a straight line on a frictionless horizontal surface. Its displacement from the origin is given by
x = (16 cm)cos[(16 rad/s)t + π/2 rad]


What force, applied to the block by the spring, results in the given oscillation?

why can you not just do F=ma?

  • physics please! -

    An oscillating force is applied by the spring. You can use F = ma

    The force required to make this motion happen is
    F = ma = m * d^2x/dt^2
    = -16^2 * (0.16m) m cos [(16 rad/s)t + π/2 rad]
    = -256 m x Newtons

    (If x is in meters)

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