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The thermal decomposition of potassium chlorate can be used to produce oxygen in the laboratory.

What volume (L) of O2 gas at 25 °C and 1.00 atm pressure is produced by the decomposition of 7.5 g of KClO3 (s)?

Here is my work:


.0611995 mol of O2 x .0821Latm/molL x298.15K / 1.0atm=1.498

Why is 1.498 incorrect?

  • Chemistry -

    .0611995 mol of KClO3 needed to be converted to .09179925 mol of O2 b/c of the coeficients

  • Chemistry -

    The answer is correct except for not being labeled and not rounded off correctly.

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