I need to find the quotient function of the following:
Given that f(x)=x^2-3 and g(x)=2x+1 find each of the following if it exists:
a. (f/g)(-root3)
b. (g/f)(-1/2)
Here we go again, same question!
Are you people all in the same class?
Laurie 8:39 pm Sunday
http://www.jiskha.com/display.cgi?id=1245026379
Robert 11:58 am Sunday
http://www.jiskha.com/display.cgi?id=1244995082
Crystal 10:06 am Sunday
http://www.jiskha.com/display.cgi?id=1244988379
Breanna 11:44 Friday
http://www.jiskha.com/display.cgi?id=1244864678
It was answered by dwrls back on Friday to Breanna
That is not what the ? is asking. The ? is asking about how to get the quotient function, not the composite as you solved for. Can you please show us how to get the quotient function solution? Thanks!
To find the quotient function, (f/g)(x), we need to divide the function f(x) by the function g(x).
a. To find (f/g)(-√3), we need to evaluate the quotient function at x = -√3.
Step 1: Find the value of f(-√3)
Substitute x = -√3 into the function f(x)
f(-√3) = (-√3)^2 - 3
= 3 - 3
= 0
Step 2: Find the value of g(-√3)
Substitute x = -√3 into the function g(x)
g(-√3) = 2(-√3) + 1
= -2√3 + 1
Step 3: Evaluate (f/g)(-√3)
(f/g)(-√3) = f(-√3) / g(-√3)
= 0 / (-2√3 + 1)
= 0
So, (f/g)(-√3) = 0.
b. To find (g/f)(-1/2), we need to evaluate the quotient function at x = -1/2.
Step 1: Find the value of g(-1/2)
Substitute x = -1/2 into the function g(x)
g(-1/2) = 2(-1/2) + 1
= -1 + 1
= 0
Step 2: Find the value of f(-1/2)
Substitute x = -1/2 into the function f(x)
f(-1/2) = (-1/2)^2 - 3
= 1/4 - 3
= -2 3/4
Step 3: Evaluate (g/f)(-1/2)
(g/f)(-1/2) = g(-1/2) / f(-1/2)
= 0 / (-2 3/4)
= 0
So, (g/f)(-1/2) = 0.
Therefore, the quotient function (f/g)(x) = 0 for any value of x.