Find the distance between P(7,-4)and the line with equation x-3y+5=0.Round to the nearest tenth.
The perpendicular distance D of a point P(x0,y0) to the line Ax + By + C = 0 is
D = ( Ax0 + By0 + C ) / sqrt(A2 + B2)
In the given problem,
A=1
B=-3
C=5
Plrsdr post your answer if you'd like to have a check.