PreAlgebra
posted by mysterychicken .
How can I solve this problem, I'm stuck on it:
Approximate to the nearest hundreth by interpolation
5*square root of 84.4
Thanks
MC

You probably need to use some tables to interpolate.
But without those, nine squared is 81
10 squared is 100
Using that, which is rather loose, then
the difference in 84.4 and 81 is 3.4
the difference in 81 and 100 is 19
so 3.4/19 = x/1 where x is the addition to 9.0
x=.179
Square root of 84.4 then is 9.18 to the nearest hundredth, approximately 
Thank you so much bobpursley!
MC
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