In general, which reaction(forward, reverse, or neither) is favored if the value of K at a specified temperature is

a. equal to 1?
b. very small
c. very large

i was thinking of b

Think again. What does K mean?

kelvin so c

That answer is crazy. Keq is NOT Kelvin. And it appears to me that your question actually is three questions. They want to know three separate answers for a,b, and c.

so how do you answer it

i have this same question and I am so losed

For a reaction, such as

A + B ==> C + D

Keq = (C)*(D)/(A)*(B)
So for K to be small, the numerator must be small and/or the denominator must large (that's the only way to get a small number out of a fraction), so C and D must be small and/or A and B large; therefore, the reaction does not proceed to a large extent. That is, A and B simply do not react to a great extent. For Keq to be large, then the numerator must be large and/or the denominator must be small which means the products over shadow the reactants and the reaction proceeds. That is, the products are favored over the reactants. For Keq = 1, products must be equal to reactants and the reaction is about 50-50.