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Find the distance between P(-4,3) and the line with equation: 2x - 5y = -7
a. (14√29)/29
b. 0
c. (-16√29)/29
d. (16√29)/29

I got C but would it be positive, like D?

  • Math -

    You are finding distance, so it would be the absolute value, namely D

    Are you using the method
    for a point (p,q) to the line Ax + By + C = 0
    distance = │Ap + Bq + C│/√(A^2+B^2) ?

  • Math -

    oh okay, thought so

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