# Algebra

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(-3a^-5 b^6)^4 (a^7b^0)^3

• Algebra -

First, I will assume that the -3 at the beginning will not be raised to the -5th power.

A little revision of the law of indices is in order:

(ab)^n = a^n . b^n
this will apply to the ^4 and ^3 outside of the parentheses.

a^-n=1/a^n
This will apply to the term a^-5

b^0 = 1
for all values of b except 0.

(-3a^-5 b^6)^4 (a^7b^0)^3
=(-3b^6/a^5)^4 (a^7 . 1)^3
=(-3)^4 (b^6)^4 /(a^5)^4 (a^7)^3
= (-3)^4 (b^24)/(a^20) (a^21)
= ...
I will let you take it from here.

=

• Algebra -

Ok thanks! I got 81ab^24 Is this correct? Thanks!

• Algebra -

Do start the problem over to understand every step.

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