posted by Sydney .
The equation describing the velocity of the ice falling from the wing as a function of time is v=45(1-(0.804)^t). Determine algebraically the time required, to the nearest tenth of a second, for the ice to reach a velocity of 98% of its terminal velocity of 45 m/s.
Please help me. Thank-you!
Since it is not specified in the question, we will assume that the equation for v as a function of time is in m/s.
where t is in seconds.
A plot of the graph of v(t) versus t will shed some light.
Let v1=98% of terminal velocity of 45 m/s
then we look for the value of t1 such that
45*(1-0.804^t1) = 45*0.98
Can you take it from here?
Hint: solve for t1 either by trial and error or apply the laws of logarithm.