Write an equation of the tangent function with period (3π)/8, phase shift -π/5, and vertical shift -2.
a. y=tan((8x)/3 - (8π)/15) -2
b. y=tan((8x)/3 + (8π)/15) -2
c. y=tan((16x)/3 +(3π)/80) -2
d. y=tan((8x)/3 - (3π)/40) -2
Use an addition or subtraction formula to write the expression as a trigonometric function of one number, and then find its exact value. (tan(π/2)+tan((2π)/3)) / (1-tan(π/2)tan((2π)/3)) Answer=__________ Exact value …
How do I find the critical values? y= 4/x + tan(πx/8) What I did is I simplified it to y= 4x^-1 + tan(πx/8) then I took the derivative y'= -4x^-2 + (π/8)(sec(πx/8))^2 Then I simplied it y'= -4/x^2 + (π/8)(sec(πx/8))^2