High it's me again...
uh how do I write this in SRform?
(7^2^-1+2^2^-1)^2
I tried writing it out in expanded form and
I got
98^2^-1+28^2^-1
which is wrong so how do i do this?
To write the expression (7^2^-1+2^2^-1)^2 in simplified radical form, we need to follow a few steps:
Step 1: Evaluate the exponents inside the parentheses.
Since 2^-1 means the reciprocal of 2, we can rewrite 7^2^-1 as 7^(1/2) and 2^2^-1 as 2^(1/2).
Step 2: Simplify the expression inside the parentheses.
Adding the two terms, we have 7^(1/2) + 2^(1/2).
Step 3: Rewrite the expression using the concept of rationalizing the denominator.
The goal is to eliminate the radicals from the denominator. To do this, we need to multiply both the numerator and the denominator by the conjugate of the denominator.
Multiplying by the conjugate, we have:
(7^(1/2) + 2^(1/2))(7^(1/2) - 2^(1/2))
Step 4: Apply the product of a sum and difference formula.
The product of a sum and difference is in the form (a + b)(a - b) = a^2 - b^2.
Applying this formula, we get:
(7^(1/2))^2 - (2^(1/2))^2
This simplifies to:
7^(1/2 * 2) - 2^(1/2 * 2)
= 7 - 2
= 5
Step 5: Finally, square the result.
Taking the result of 5 and squaring it, we get:
5^2 = 25
Therefore, the simplified radical form of (7^2^-1+2^2^-1)^2 is 25.