determine how many mL's of a monohydroxic base with a pH of 9 is needed to neutralize 50 mL of a monoprotic acid with a pH of 2. I do not understand what to do. can someone please help?
the H+ must equal the OH-
H+=10^-9=> OH=10^-5
H+=10^-2
50*10^-2=V*10-5
V=50ml*10^3 or 50 liters
To solve this problem, we need to understand the concept of pH, acid-base neutralization, and the stoichiometry of the reaction.
First, let's define some key concepts:
- pH: pH is a measure of the acidity or alkalinity of a solution. It is a logarithmic scale ranging from 0 to 14, with 7 being neutral. A pH less than 7 indicates acidity, while a pH greater than 7 indicates alkalinity.
- Acid: An acid is a substance that releases hydrogen ions (H+) in a solution, leading to an increase in the concentration of H+ ions and a decrease in pH.
- Base: A base is a substance that accepts or combines with H+ ions, decreasing their concentration and increasing the pH of a solution.
- Neutralization: When an acid reacts with a base, they undergo a chemical reaction called neutralization, forming water and a salt. The pH of the resulting solution is close to 7.
Now, let's step-by-step solve the problem:
1. Determine the number of moles of the monoprotic acid:
To find the number of moles, we need to use the pH of the monoprotic acid. Since the pH is 2, we know that the concentration of H+ ions is 10^(-2) M (from the pH scale definition). As it is a monoprotic acid, it will release one mole of H+ ions per mole of acid.
2. Find the volume of the monoprotic acid in liters:
We are given that the monoprotic acid has a volume of 50 mL. To convert this to liters, divide by 1000: 50 mL / 1000 = 0.05 L.
3. Calculate the number of moles of the monoprotic acid:
Multiply the concentration (10^(-2) M) by the volume in liters (0.05 L) to get the number of moles: 10^(-2) M * 0.05 L = 5 * 10^(-4) moles.
4. Determine the number of moles of the monohydroxic base:
To neutralize the acid, the number of moles of the monohydroxic base should be equal to the number of moles of the acid. This is based on the principle of stoichiometry and the balanced equation of the neutralization reaction. Since it is not provided, we assume it is 1:1.
5. Find the volume of the monohydroxic base in liters:
We are trying to find the volume in mL, so we need to convert it to liters. At this point, we don't have the concentration or any other information to perform this conversion.
At this stage, we need more information to proceed with the calculation. We need the concentration of the monohydroxic base. Once you have this information, you can proceed with the following step:
6. Calculate the volume of the monohydroxic base:
Divide the number of moles of the monohydroxic base by its concentration to find the volume in liters.
I hope this explanation helps you understand the steps to solve the problem. Remember to gather all the necessary information before continuing with the calculation.