posted by maddie .
I'm quite clueless as to how to solve this. I know the quadratic equation but am not sure how to get this equation into the format to plug in to the quadratic...
Solve the quadratic equation using the formula [1/(1+x)]-[1/(3-x)]=(6/35)
Show your work
multiply both sides by 35(x+1)(x-3)
and you should be able to assemble it from there.
so should i just multiply that all out and then plug it in?
Write the two terms on the left with a common denomimnator. Then convert to standard quadratic form.
[(3-x) - (1+x)]/[(1+x)(3-x)] = 6/35
(2-2x)/[(1+x)(3-x)] = 6/35
(1-x) = (3/35)[(1+x)(3-x)]
35 -35x = 3[-x^2 +2x +3)
3x^2 -41x +26 = 0
Check my work. No guarantees
We were lucky that one factored fairly easily. x = 2/3 or 13
i got the same answer but used the quadratic :) thank you for all your help everyone!