1C2H6+2O2 yields 3H2O + 2CO2 would this be the hydrocarbon butene? If I did this wrong, how would you correctly identify this hydrocarbon? Thanks for your help.
It is C2H6, ethane.
http://en.wikipedia.org/wiki/Ethane
Memorize the alkanes through octane. Then -enes, and -ynes are easy
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click on the left on alkanes.
To determine if the given chemical equation represents the hydrocarbon butene, we need to analyze the molecular formula on both sides of the equation.
In the equation, 1C2H6 + 2O2 yields 3H2O + 2CO2:
1C2H6 represents 1 molecule of ethane.
2O2 represents 2 molecules of oxygen.
3H2O represents 3 molecules of water.
2CO2 represents 2 molecules of carbon dioxide.
Based on the molecular formulas, we can determine that the hydrocarbon involved in this reaction is not butene. Instead, it is ethane (C2H6). Butene has a different molecular formula, C4H8.
To correctly identify the hydrocarbon in a chemical equation, you need to check the molecular formula of the hydrocarbon on the reactant side. If the hydrocarbon is stated as a product, then you can determine it by analyzing the other products and reactants and balancing the equation if necessary.
For example, to identify butene in a balanced equation, you would expect to see a hydrocarbon with a molecular formula of C4H8 on the reactant side. You would then balance the equation, ensuring that the number of carbon and hydrogen atoms correspond to the molecular formula of butene.
I hope this explanation helps! If you have any further questions, feel free to ask.