the perimeter of the square is 204 ft. what is the value of x if 1 side of the square is 5x+6 ft
then
(5x+6)(5x+6) = 204
(5x+6)^2 = 204
5x+6 = ± √204 but x is sureley positive, so
x = (√204 - 6)/5 = (2√51 - 6)/5 or appr. 1.6567
204 / 4 = 51
5x + 6 = 51
5x = 45
x = ?
silly me, read the question wrong and made it harder than it had to be.
To find the value of x, we can use the formula for the perimeter of a square, which is equal to four times the length of one side of the square.
Let's assume the length of one side of the square is represented by the expression 5x + 6 ft.
According to the given information, the perimeter of the square is 204 ft. Therefore, we can set up an equation:
Perimeter of the square = 4 * (5x + 6) ft
204 ft = 4 * (5x + 6) ft
Now, we can solve for x:
Divide both sides of the equation by 4:
(204 ft) / 4 = (4 * (5x + 6)) / 4
51 ft = 5x + 6
Next, subtract 6 from both sides of the equation:
51 ft - 6 = 5x + 6 - 6
45 ft = 5x
Finally, divide both sides of the equation by 5:
(45 ft) / 5 = (5x) / 5
9 ft = x
Therefore, the value of x is 9.