What is an equation of the line that passes through the points (3,-3) and (-3,-3)? how do you figure this out:

a. y=3
b. x=-3
c. y=-3
d. x=y

y is the same, so y=-3 is the equation

Thanks

To find the equation of a line that passes through two given points, you can use the point-slope form of a linear equation.

Given the points (3, -3) and (-3, -3), we can calculate the slope (m) first.

The formula for slope (m) between two points (x1, y1) and (x2, y2) is:
m = (y2 - y1) / (x2 - x1)

Let's calculate the slope using the given points:
m = (-3 - -3) / (-3 - 3)
m = 0 / -6
m = 0

Since the slope (m) is zero, this means it is a horizontal line.

Now, we need to find the y-intercept (b). We can substitute the values of one of the given points into the equation and solve for b.

Using the first point (3, -3) and the slope (0):
-3 = 0 * 3 + b
-3 = b

Now that we have the slope (m = 0) and the y-intercept (b = -3), we can write the equation for the line in slope-intercept form (y = mx + b).
Therefore, the equation of the line passing through the points (3, -3) and (-3, -3) is y = -3.

The correct answer is:
c. y = -3