Math
posted by Sarah .
(2,14),(1,1),(3,35)
Find the quadratic function y=ax^2+bx+c
1) 4a+2b+c=14
2) a+b+c=1
3) 9a+3b+c= 35
equation 1&2 = 3a + b = 13
equation 1&3 = 5a +5b = 21
i know you take those two equations now
3a + b = 13
5a  5b = 21
multiply the top by 5 and the bottom equation by 3
15a + 5b = 65
15a  15b = 63
that
10b = 2
but its suppose to come out to a whole number what am i doing wrong???
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