If 6.90 g of (half-life = 5.30 y) are allowed to decay, how many grams would be left after 1.00 y and after 10.0 y?
Calculate k.
k = 0.693/t(1/2)
Then put k into the following:
ln(No/N) = kt
No = 6.90 g
N = solve for that.
i did that! i got 7.86 but its wrong what di dyou get?
For the 1 yr it's about 6 g remaining.
For the 10 yr it's 2 g remaining.
Post your work and I'll find your error.
To answer this question, we need to understand the concept of half-life and how it relates to radioactive decay.
The half-life of a substance is the time it takes for half of the original amount to decay. For example, if you have 6.90 grams of a substance, after one half-life, you will have 3.45 grams remaining.
To calculate how many grams will be left after a certain period of time, we can use the following formula:
Amount remaining = Initial amount * (1/2)^(t / half-life)
Where:
- Initial amount is the starting amount of the substance
- t is the time that has passed
- half-life is the half-life of the substance
Let's calculate the amount of substance remaining after 1.00 year:
Amount remaining after 1.00 year = 6.90 g * (1/2)^(1 / 5.30)
Now, we can calculate the amount of substance remaining after 10.0 years:
Amount remaining after 10.0 years = 6.90 g * (1/2)^(10 / 5.30)
Using a calculator or a computer program, we can simplify the calculations and find the answers.