Question

solve for x:

logx (6+4x-x2) = 2

Answer 1

Hmmm. I did it by inspection. IF x is 3, then Logx (6-4x-x2)=log3 (6+12-9)=

log3(9)=2

How did I do it? In highscool, bases are integers. 1 is not allowed, 2 wont work, and three does, ... In the real world, bases can be any number. Frankly, I don't see an easy way to do it without this type of arguement.