the base of an isosceles triangle i 5 and its perimeter is 1. the base of a similar isosceles triangle is 10. what is the perimeter of the larger triangle?
1 15
2 21
3 22
4 110
I think you mistyped the perimeter. Set the problem up
base i/perimeter i = other base/perimeter
the multiply across the equal sign top to bottom then divide by the other number. using what you have given above, it would be
5/1 = 10/x
10 times 1 divided by 5 so the answer would be 2. They are all set up the same, no matter your numbers.
To find the perimeter of the larger triangle, we need to find the ratio of the lengths of corresponding sides in the two triangles. Since the triangles are similar, the ratio of corresponding sides is the same.
In this case, we know that the base of the smaller triangle is 5 and the base of the larger triangle is 10. So, the ratio of the bases is 10/5 = 2.
Since the bases are in a 2:1 ratio, we can conclude that the other two sides of the larger triangle are also in a 2:1 ratio with the corresponding sides of the smaller triangle.
Let's call one of the equal sides of the smaller triangle as x. Then, the length of the other equal side of the smaller triangle is also x.
Similarly, for the larger triangle, let's call one of the equal sides as 2x. Then, the length of the other equal side of the larger triangle is also 2x.
Now, let's find the value of x. The perimeter of the smaller triangle is 1, which means the sum of all three sides is 1. So, we can write:
5 + x + x = 1
2x + 5 = 1
2x = 1 - 5
2x = -4
x = -2
Since side lengths cannot be negative, we made a mistake somewhere in our calculations.
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