Algebra
posted by Kelsie .
Factor the numerator and denominator of each fraction if neceesary. Rewrite each one as a product. Then look for ones and simplify. The denominator is not zero.
x^2+6x+9 2x^2x10 28x^2x15
  
x^29 3x^2+7x+2 28x^2x15
x^2+4x

2x+8

Algebra 
Reiny
very hard to figure out what you typed.
Please use brackets next time, building fractions in this format does not work.
I think you meant:
(x^2+6x+9)/(x^29) * (2x^2x10)/(x^2+7x+2) * (28x^2x15)/(28x^2x15)
I assume you know how to factor, since this is usually the type of exercise with that topic
= (x+3)(x+3)/[(x3)(x+3)] * (2x5)(x+2)/[(3x+1)(x+2)] * (28x^2x15)/(28x^2x15)
= (x+3)(2x5)/[(x+3)(3x+1) , x not equal to 3,1/3
I did not attempt to factor the last part, since it just canceled.
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